How To Solve Second Six Levels Of River Crossing IQ Game

River Crossing IQ game is just fun. Need help to solving the levels? Here is another.

Know how to solve next six levels as I had post for solving first six levels of River Crossing IQ Game. Below are next next six levels of River Crossing IQ Game, it may differ from your version of game.

Start solving River Crossing IQ Game

This post contains another six levels of River Crossing IQ Game. Have fun solving it.

There are 6 frogs and 7 pillars

There are 6 frogs and 7 pillars

There are 6 frogs and 7 pillars

Logic 7: There are 6 frogs and 7 pillars, swap these 6 frogs into two groups of 3, provided that frogs can not jump back, the longest distance they can jump is 2 pillars.
Solution: Name the frogs on left side L1, L2 and L3 same with frogs on right side R1, R2 and R3.

Steps
L3
R1
R2
L3
L2
L1
R1
R2
R3
L3
L2
L1
R2
R3
L1

There are 3 cups of 8L, 5L, 3L

There are 3 cups of 8L, 5L, 3L

There are 3 cups of 8L, 5L, 3L

Logic 8: There are 3 cups of 8L, 5L, 3L. The cup of 8L was filled with beer. Pour out 4L of beer within 10 times of pouring.
Solution:

Steps
8L to5L
5L to 3L
3L to 8L
5L to 3L
8L to 5L
5L to 3L

Aside the river there are 1 police, 1 robber, 1 blond hair woman and 2 children

Aside the river there are 1 police, 1 robber, 1 blond hair woman and 2 children

Aside the river there are 1 police, 1 robber, 1 blond hair woman and 2 children

Logic 9: Aside the river there are 1 police, 1 robber, 1 blond hair woman and 2 children, 1 red hair woman and 2 children. There is a boat carrying a maximum of 2 people. Only adults can sail but not kids. Please help all people move across the river, knowing that if the policeman is absent, the robber will kill all people there. If the blond hair woman is absent, the red hair woman will beat the blond hair woman’s children (and vice versa).
Solution:
Let the left island = A and right island = B
Blond hair woman and her children be BW, B1 and B2
Red hair woman and her children be RW, R1 and R2

Steps
First pick police man and robber to A. Drop the robber and police man back to B.
Police man sail with B1 to A and back with robber to B.
Now BW and B2 sail and drop B2 to A, BW back to B.
Now women sail to A, BW stay and RW back to B.
Police man and robber sail to A, they two stay on A and BW sail to B.
Women sail to A, BW stay and RW go back to B.
Now RW sail with R1 to A. Both stay and police man with robber goes back to B.
Robber stays, police man with R2 sail to A.
Police man goes back to B and sail with robber to A.

Move all of these rings to the destination pillar after 33 moves

Move all of these rings to the destination pillar after 33 moves

Move all of these rings to the destination pillar after 33 moves

Logic 10: Please move all of these rings to the destination pillar after 33 moves. Knowing that in the process of moving, the large ring can not be located on the smaller ring.
Solution: Name pillars from left to right P1, P2 and P3. Rings from smaller to larger R1, R2, R3, R4 and R5.

Steps
R1 to P3
R2 to P2
R1 to P2
R3 to P3
R1 to P1
R2 to P3
R1 to P3
R4 to P2
R1 to P2
R2 to P1
R1 to P1
R3 to P2
R1 to P3
R2 to P2
R1 to P2
R5 to P3
R1 to P1
R2 to P3
R1 to P3
R3 to P1
R1 to P2
R2 to P1
R1 to P1
R4 to P3
R1 to P3
R2 to P2
R1 to P2
R3 to P3
R1 to P1
R2 to P3
R1 to P3

Help 3 men with 3 correlative money bags move to the other side of the river

Help 3 men with 3 correlative money bags move to the other side of the river

Help 3 men with 3 correlative money bags move to the other side of the river

Logic 11: Help 3 men with 3 correlative money bags move to the other side of the river. Note: If at any side of the river, the total amount of money in the bags greater than the total value of money owned by these men there, the men would steal the money and escape.
Solution: Let red man = RM, blue man = BM and yellow man = YM. Red bag = RB, blue bag = BB and yellow bag = YB.
Left island = A and right island = B.

Steps
YM with YB to A. YM back to B.
RM with BB to A, drop bag and back to B.
YM and BM sail to A.
YM with YB sail to B and stay with bag.
RM with RB sail to A and stay with bag.
BM with BB go to B and drop bag.
BM and YM sail to A, both stay and RM go to B.
RM pick YB from B and stay at A.
BM take BB from B and sail to A.

Switch places of the 2 black and yellow seahorses

Switch places of the 2 black and yellow seahorses

Switch places of the 2 black and yellow seahorses

Logic 12: Please switch places of the 2 black and yellow seahorses, knowing that the seahorses moves like a knight in chessboard.
Solution: Let yellow seahorses be y1 and y2. Black seahorses be B1 and B2.
Now we name the places from top left to bottom right 1, 2, 3, 4, 5, 6, 7, 8 and 9.
Steps
y2 to 6.
B2 to 2.
B1 to 4.
Y1 to 8.
Y2 to 1.
B2 to 7.
B1 to 9.
Y1 to 3.
Y2 to 8.
B2 to 6.
B1 to 2.
Y1 to 4.
Y2 to 3.
B2 to 1.
B1 to 7.
Y1 to 9.